Optimal. Leaf size=286 \[ \frac{12 b^{5/4} \sqrt [4]{c} x \left (\sqrt{b}+\sqrt{c} x\right ) \sqrt{\frac{b+c x^2}{\left (\sqrt{b}+\sqrt{c} x\right )^2}} \text{EllipticF}\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{c} \sqrt{x}}{\sqrt [4]{b}}\right ),\frac{1}{2}\right )}{5 \sqrt{b x^2+c x^4}}-\frac{24 b^{5/4} \sqrt [4]{c} x \left (\sqrt{b}+\sqrt{c} x\right ) \sqrt{\frac{b+c x^2}{\left (\sqrt{b}+\sqrt{c} x\right )^2}} E\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{c} \sqrt{x}}{\sqrt [4]{b}}\right )|\frac{1}{2}\right )}{5 \sqrt{b x^2+c x^4}}+\frac{24 b \sqrt{c} x^{3/2} \left (b+c x^2\right )}{5 \left (\sqrt{b}+\sqrt{c} x\right ) \sqrt{b x^2+c x^4}}+\frac{12}{5} c \sqrt{x} \sqrt{b x^2+c x^4}-\frac{2 \left (b x^2+c x^4\right )^{3/2}}{x^{7/2}} \]
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Rubi [A] time = 0.301089, antiderivative size = 286, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 7, integrand size = 21, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.333, Rules used = {2020, 2021, 2032, 329, 305, 220, 1196} \[ \frac{12 b^{5/4} \sqrt [4]{c} x \left (\sqrt{b}+\sqrt{c} x\right ) \sqrt{\frac{b+c x^2}{\left (\sqrt{b}+\sqrt{c} x\right )^2}} F\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{c} \sqrt{x}}{\sqrt [4]{b}}\right )|\frac{1}{2}\right )}{5 \sqrt{b x^2+c x^4}}-\frac{24 b^{5/4} \sqrt [4]{c} x \left (\sqrt{b}+\sqrt{c} x\right ) \sqrt{\frac{b+c x^2}{\left (\sqrt{b}+\sqrt{c} x\right )^2}} E\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{c} \sqrt{x}}{\sqrt [4]{b}}\right )|\frac{1}{2}\right )}{5 \sqrt{b x^2+c x^4}}+\frac{24 b \sqrt{c} x^{3/2} \left (b+c x^2\right )}{5 \left (\sqrt{b}+\sqrt{c} x\right ) \sqrt{b x^2+c x^4}}+\frac{12}{5} c \sqrt{x} \sqrt{b x^2+c x^4}-\frac{2 \left (b x^2+c x^4\right )^{3/2}}{x^{7/2}} \]
Antiderivative was successfully verified.
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Rule 2020
Rule 2021
Rule 2032
Rule 329
Rule 305
Rule 220
Rule 1196
Rubi steps
\begin{align*} \int \frac{\left (b x^2+c x^4\right )^{3/2}}{x^{9/2}} \, dx &=-\frac{2 \left (b x^2+c x^4\right )^{3/2}}{x^{7/2}}+(6 c) \int \frac{\sqrt{b x^2+c x^4}}{\sqrt{x}} \, dx\\ &=\frac{12}{5} c \sqrt{x} \sqrt{b x^2+c x^4}-\frac{2 \left (b x^2+c x^4\right )^{3/2}}{x^{7/2}}+\frac{1}{5} (12 b c) \int \frac{x^{3/2}}{\sqrt{b x^2+c x^4}} \, dx\\ &=\frac{12}{5} c \sqrt{x} \sqrt{b x^2+c x^4}-\frac{2 \left (b x^2+c x^4\right )^{3/2}}{x^{7/2}}+\frac{\left (12 b c x \sqrt{b+c x^2}\right ) \int \frac{\sqrt{x}}{\sqrt{b+c x^2}} \, dx}{5 \sqrt{b x^2+c x^4}}\\ &=\frac{12}{5} c \sqrt{x} \sqrt{b x^2+c x^4}-\frac{2 \left (b x^2+c x^4\right )^{3/2}}{x^{7/2}}+\frac{\left (24 b c x \sqrt{b+c x^2}\right ) \operatorname{Subst}\left (\int \frac{x^2}{\sqrt{b+c x^4}} \, dx,x,\sqrt{x}\right )}{5 \sqrt{b x^2+c x^4}}\\ &=\frac{12}{5} c \sqrt{x} \sqrt{b x^2+c x^4}-\frac{2 \left (b x^2+c x^4\right )^{3/2}}{x^{7/2}}+\frac{\left (24 b^{3/2} \sqrt{c} x \sqrt{b+c x^2}\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{b+c x^4}} \, dx,x,\sqrt{x}\right )}{5 \sqrt{b x^2+c x^4}}-\frac{\left (24 b^{3/2} \sqrt{c} x \sqrt{b+c x^2}\right ) \operatorname{Subst}\left (\int \frac{1-\frac{\sqrt{c} x^2}{\sqrt{b}}}{\sqrt{b+c x^4}} \, dx,x,\sqrt{x}\right )}{5 \sqrt{b x^2+c x^4}}\\ &=\frac{24 b \sqrt{c} x^{3/2} \left (b+c x^2\right )}{5 \left (\sqrt{b}+\sqrt{c} x\right ) \sqrt{b x^2+c x^4}}+\frac{12}{5} c \sqrt{x} \sqrt{b x^2+c x^4}-\frac{2 \left (b x^2+c x^4\right )^{3/2}}{x^{7/2}}-\frac{24 b^{5/4} \sqrt [4]{c} x \left (\sqrt{b}+\sqrt{c} x\right ) \sqrt{\frac{b+c x^2}{\left (\sqrt{b}+\sqrt{c} x\right )^2}} E\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{c} \sqrt{x}}{\sqrt [4]{b}}\right )|\frac{1}{2}\right )}{5 \sqrt{b x^2+c x^4}}+\frac{12 b^{5/4} \sqrt [4]{c} x \left (\sqrt{b}+\sqrt{c} x\right ) \sqrt{\frac{b+c x^2}{\left (\sqrt{b}+\sqrt{c} x\right )^2}} F\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{c} \sqrt{x}}{\sqrt [4]{b}}\right )|\frac{1}{2}\right )}{5 \sqrt{b x^2+c x^4}}\\ \end{align*}
Mathematica [C] time = 0.0158831, size = 56, normalized size = 0.2 \[ -\frac{2 b \sqrt{x^2 \left (b+c x^2\right )} \, _2F_1\left (-\frac{3}{2},-\frac{1}{4};\frac{3}{4};-\frac{c x^2}{b}\right )}{x^{3/2} \sqrt{\frac{c x^2}{b}+1}} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.185, size = 216, normalized size = 0.8 \begin{align*}{\frac{2}{5\, \left ( c{x}^{2}+b \right ) ^{2}} \left ( c{x}^{4}+b{x}^{2} \right ) ^{{\frac{3}{2}}} \left ( 12\,{b}^{2}\sqrt{{\frac{cx+\sqrt{-bc}}{\sqrt{-bc}}}}\sqrt{2}\sqrt{{\frac{-cx+\sqrt{-bc}}{\sqrt{-bc}}}}\sqrt{-{\frac{cx}{\sqrt{-bc}}}}{\it EllipticE} \left ( \sqrt{{\frac{cx+\sqrt{-bc}}{\sqrt{-bc}}}},1/2\,\sqrt{2} \right ) -6\,{b}^{2}\sqrt{{\frac{cx+\sqrt{-bc}}{\sqrt{-bc}}}}\sqrt{2}\sqrt{{\frac{-cx+\sqrt{-bc}}{\sqrt{-bc}}}}\sqrt{-{\frac{cx}{\sqrt{-bc}}}}{\it EllipticF} \left ( \sqrt{{\frac{cx+\sqrt{-bc}}{\sqrt{-bc}}}},1/2\,\sqrt{2} \right ) +{c}^{2}{x}^{4}-4\,bc{x}^{2}-5\,{b}^{2} \right ){x}^{-{\frac{7}{2}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (c x^{4} + b x^{2}\right )}^{\frac{3}{2}}}{x^{\frac{9}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{\sqrt{c x^{4} + b x^{2}}{\left (c x^{2} + b\right )}}{x^{\frac{5}{2}}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (x^{2} \left (b + c x^{2}\right )\right )^{\frac{3}{2}}}{x^{\frac{9}{2}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (c x^{4} + b x^{2}\right )}^{\frac{3}{2}}}{x^{\frac{9}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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